Construct a 95% confidence interval for the population proportion of people in New Hampshire

Posted: September 7th, 2022

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You are told that a random sample of 150 people from Manchester New Hampshire have been given cholesterol tests, and 60 of these people had levels over the “safe” count of 200.
Using Excel, construct a 95% confidence interval for the population proportion of people in New Hampshire with cholesterol levels over 200.
Note: Note that this question requires confidence interval for a proportion, the interval that is likely to capture the proportion of all population members’ that satisfy a specified property. Do you remember the formula? If not, here it is:
p estimate + – z-critical value X sqrt (p estimate (1-p estimate)/n)
Also note that, for population proportion, we use z-multiple not the t-multiple. So you can ask, where is the population standard deviation? You don’t need it. Look at the formula.

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